(-x+3)^2=(-x-2)(-x+3)

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Solution for (-x+3)^2=(-x-2)(-x+3) equation: 



(-x+3)^2=(-x-2)(-x+3)

We move all terms to the left:

(-x+3)^2-((-x-2)(-x+3))=0

We add all the numbers together, and all the variables

(-1x+3)^2-((-1x-2)(-1x+3))=0

We multiply parentheses ..

-((+x^2-3x+2x-6))+(-1x+3)^2=0



We calculate terms in parentheses: -((+x^2-3x+2x-6)), so:

(+x^2-3x+2x-6)

We get rid of parentheses

x^2-3x+2x-6

We add all the numbers together, and all the variables

x^2-1x-6

Back to the equation:

-(x^2-1x-6)



We get rid of parentheses

-x^2+1x+(-1x+3)^2+6=0

We add all the numbers together, and all the variables

-1x^2+x+(-1x+3)^2+6=0

We move all terms containing x to the left, all other terms to the right

-1x^2+x+(-1x+3)^2=-6

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